Refactor as function.

challenge3.py

@@ -1,10 +1,12 @@
 # single-byte xor cipher
 from binascii import unhexlify
-hexed = "1b37373331363f78151b7f2b783431333d78397828372d363c78373e783a393b3736"
-unHexed = unhexlify(hexed)
-alphabet = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']
 
+
+def xor_SingleByte(hexed):
+    alphabet = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']
+    unHexed = unhexlify(hexed)
     # generate a dict of possible answers and their decryption keys
+    
     tableOfPossibleAnswers = {}
     for code in range(256):
         possibleAnswer = ''.join(chr(byte ^ code) for byte in unHexed)
@@ -31,3 +33,6 @@ for key in weightedCodes:
     for key,value in tableOfPossibleAnswers.items():
         if tableOfPossibleAnswers[key] == answerValue:
             print(key, tableOfPossibleAnswers[key])
+
+
+xor_SingleByte("1b37373331363f78151b7f2b783431333d78397828372d363c78373e783a393b3736")